AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |
Back to Blog
![]() ![]() One can show that the sum of the angles in both media (relative to the direction for normal incidence) is 90°.Īs a numerical example, one can consider light coming from air ( n 1 ≈ 1) to a glass with n 2 = 1.5.įor that situation, one can calculate that Brewster's angle is ≈56.3°.įigure 2 shows Brewster's angle as a function of the ratio of refractive indices – or the refractive index of the second medium, if the first medium has n 1 = 1. Here, n 1 and n 2 are the refractive indices of the medium of the incoming beam and the other medium, respectively. The magnitude of Brewster's angle depends on the refractive indices of the involved optical media and can be calculated with Brewster's law: The latter condition means that the polarization direction (i.e., the direction in which the electric field vector oscillates) lies within the plane of incidence.įor s-polarized light, the reflectivity is even higher than for light with normal incidence on the boundary. However, for a particular angle of incidence, which is called Brewster's angle (after Sir David Brewster) or sometimes polarizing angle, that reflection does not occur provided that the light is p-polarized. ![]() When light impinges on a flat boundary between two different transparent media, generally at least some part of its optical power is reflected. How to cite the article suggest additional literatureįor obtaining vanishing reflection losses at a Brewster plate, the angle of incidence has to be close to Brewster's angle, and the light must be p-polarized, i.e., the polarization direction is in the plane of incidence (here: the drawing plane). Encyclopedia > letter B > Brewster's angle Brewster's Angleĭefinition: an angle of incidence at which there is no reflection of p-polarized light at an uncoated optical surface
0 Comments
Read More
Leave a Reply. |